WebMar 6, 2012 · Okay, the first thing you need to know is how to append things to a vector. Easily enough the function you want is append: x <- c (1, 2) x <- append (x, 3) will make the vector x contain (1, 2, 3) just as if you'd done x <- (1, 2, 3). The next thing you need to realise is that each member of your target vector is double the one before, this is ... WebOct 12, 2024 · Here is a completely generic example on how to fill a matrix using for -loops in R: m = 100 n = 20 o = matrix (data = NA, nrow = m, ncol = n) for ( i in 1:m ) { for ( j in 1:n ) { o [i,j] = rnorm (n = 1) } } Or filling by row: m = 100 n = 20 o = matrix (data = NA, nrow = m, ncol = n) for ( i in 1:m ) { o [i,] = rnorm (n = n) }
Filling a matrix sequentially using for loop in R - Stack Overflow
WebDec 21, 2013 · You can proceed as follows: #extract the correlation r from LD results tc<-LD.object$"r" #build a three columns matrix with all the pairwise combination of two markers pwm<-combn (row.names (tc),2) pwld<-matrix (NA,nrow=ncol (pwm),ncol=3) pwld [,1:2]<-pwm [1:2,] #Fill the matrix for (aaa in 1:nrow (pwld)) { pwld [aaa,3]<-tc [pwld [aaa,1],pwld ... WebApr 18, 2024 · The best idea is to save an empty matrix first and fill it in with the for loop nsim <- 100 #how many rbinom are w n <- 100000 size = 7 prob = 0.75 sim_data_vill_for_loop <- matrix (ncol = nsim, nrow = n) for (i in seq (nsim)) #iterate from 1 to nsim sim_data_vill_for_loop [, i] <- rbinom (n, size = size, prob = prob) #fill in 1 … sbmsa football houston
R filling array by rows - Stack Overflow
WebMar 8, 2024 · I am more interested in the syntax of my for loops and conditional cell assignment, apart from that this is just dummy code: I don't need to replace values in mat but create a new matrix and fill it with values following specific conditions and equations. Nevertheless, I don't know what I am doing wrong, any help would be greatly appreciated. WebJan 11, 2024 · Learn more about matrix, matrix manipulation, matrix array, for loop, for MATLAB I need to fill matrix r, where r=r(z), and ri is constant. But with this code I onlu get the first row where r=-0.7:0.7. WebDec 18, 2024 · One issue you're having is asking R to compute dim (X), which seems, given your first code chunk, like it should be a vector and thus have a length () but not a dim (). So this solution uses your matrix Y to … sbms wiringp